educational codeforces round 133

However, $$$K + = k + cnt$$$ makes it increment by that amount instead of overwriting it. static void solve() { int n = sc.nextInt(); System.out.println(n); int[] arr = new int[n]; The only programming contests Web 2.0 platform, Educational Codeforces Round 133 (Rated for Div. 3) Educational Codeforces Round 144 (Rated for Div. I seldom solve the C in div2, but I solved it this contest and I think I will be pupil again. This round will be rated for the participants with rating lower than 2100. That's not very hard problem. 2:01:41. And it's basically the same idea. I am seeing a lot of people discussing BS solution of problem C but I dont find the approach mentioned anywhere. 2), Educational Codeforces Round 101 (Rated for Div. Marco Barbosa is the Managing Director of 14islands, a design and development studio from Stockholm in Sweden and Floripa in Brazil. Can someone explain what is wrong with this solution? If your answer is -1, then the player's rating will go 2 to 1 to 4. 2)" Codeforces div. (T_T),,CF. 2), Educational Codeforces Round 94 (Rated for Div. , Very Important I am a Newbie @787. 2], I think I just did something crazy? How this fact can be proved or even how can it be observed? First, define C[n] as the prefix sum of A[1..n] (formally: C[0] = 0, C[i] = C[i-1] + A[i] for 1 i N). 2), Educational Codeforces Round 121 (Rated for Div. 01342 -break- [104424232424004113131423112311240], 10442423 -break- [2424004113131423112311240], [] no more elements to choose [4,4] from hence answer is yes. 2) will start.. Series of Educational Rounds continue being held as Harbour.Space University initiative! Let's do better next time, although I am still a little disappointed. 2), Educational Codeforces Round 139 (Rated for Div. 1) Codeforces Round 856 (Div. This means we just ignore this subarray and do this process repeatedly: find the next index where the prefix sum is less than the same at our previous position, ignore it (since the subarray sum will be less than zero) and set that as the new position. After the end of the contest you will have 12 hours to hack any solution you want. Please who gave you the testing code? a0 1 , 0: , , 12, +1, GDAL C++ API OGRGeometry OGRPoint, Educational Codeforces Round 152 (Rated for Div. 2) . It's kinda strange but in E the small trick with changing all zeros with ones and ones with zeros, if the number of ones if more than half, works and makes O(n^2*k) solution pass. For example, do not use ideone.com with the default settings (public access to your code). This is idea, I don't know if it works, WHAT I DID STARTED WITH INDEX POINTER 0 NOW I TRAVERSE THE L AND R STRING FROM STARTING FOR EVERY DIGIT (0 , 9) IN [ L[I] , R[I] ] FOUND THE MAXIMUM INDEX IN MAIN STRING THEN SHIFTED THE INDEX POINTER TO MAXIMUM, IF NO CHAR IS PRESENT IN MAIN STRING > HENCE NO SUBSEQUENCE CAN BE GENERATED -> "YES". Just look my D solution: https://codeforces.com/contest/1845/submission/211528371, For Problem D, I have tried binary search on answer. Submission --> 211537213, First time I saw your solution, I didn't get it. thanks bud, I also had same intuition while reading the test case, but was not able to apply it through code while contest. 2), https://codeforces.com/contest/1845/submission/211518255, https://open.kattis.com/problems/colorland, https://codeforces.com/blog/entry/117727?#comment-1042026, https://codeforces.com/contest/1845/submission/211534174, https://codeforces.com/contest/1845/submission/211653651, https://codeforces.com/contest/1845/submission/211528371, submission:https://codeforces.com/contest/1845/submission/211443935, Educational Codeforces Round 152 (Rated for Div. So I could only make use of some of the input constraints. When will there be a tutorial? if it goes beyond (size of string-1) ever then possible otherwise no. Just register for practice and you will be able to submit solutions. As a green participant, I hope to be cyan again after this contest), As a cyan participant, I hope to be green again after this contest), As a blue participiant, I hope to be a LGM ever. [Educational Round 133][Codeforces 1716F. This round will be rated for the participants with rating lower than 2100. On May/12/2023 17:35 (Moscow time) Educational Codeforces Round 148 (Rated for Div. Never use someone else's code, read the tutorials or communicate with other person during a virtual contest. Now consider first range of allowed characters for first digit [l_i r_i], move the index forward until all characters in this range have appeared at least once (I used unordered_set for this). However, my A is wrong in fst. 2), Educational Codeforces Round 76 (Rated for Div. #include I was looking for binary search sol and came across yours. How to prove this ? We only need to consider blocking elements to $$$a_{i}$$$ because the total time taken to reach $$$a_{2m-i-1}$$$ from $$$a_{i}$$$ only depends on the last blocking element with position less than or equal to $$$2m-i-1$$$ (Let's call this position $$$p_{i}$$$). For example, do not use ideone.com with the default settings (public access to your code). d[j + 1][i + k + j + 1] += d[j][i] However, your current implementation results in a value of $$$cnt$$$ that is way smaller than the correct count that should be used. So in order to get the sum of all F^k, we can just look at each possible tuple, and look how many times this tuple appear across all ball selection, which is the definition of G(t). 2), Educational Codeforces Round 49 (Rated for Div. Let's consider the case when we enter the cell $$$(i,0)$$$ in time $$$t$$$ and til then we moved snakely(?). This commit does not belong to any branch on this repository, and may belong to a fork outside of the repository. If $$$n \bmod 3 = 1$$$, then there are two cases. 2), Educational Codeforces Round 114 (Rated for Div. can you please tell what helped you in AFTER READING SECOND TESTCASE DATA in TESTCASE 1 ?, i didn't get it , is this testcase so obvious for BS. Receive up to a 50% scholarship and take advantage of this opportunity to study in Barcelona and learn from industry experts while you become one yourself. Then the algorithm will be something like this: This now obviously generalizes to any positive $$$m$$$, I trust you can carry on the analysis from here :). As a cyan participant I hope to go green this round. To simulate the above process run a binary search for the first index where sum of subarray starting at k's index is negative. Educational Codeforces Round 151 [Rated for Div. For D, the editorial should probably mention how we need to keep track of the first non-zero value in each row (variable $$$mn$$$ in the solution) and only start filling it up from there, since it seems like starting from the beginning resulted in many TLEs. There is a strong independence between each digit of the final number. --> min(pref[i]) is minimum prefix value that we reached. 2), Educational Codeforces Round 45 (Rated for Div. thanks it was very helpful. Also it feels like my idea but from the opposite direction. Educational Codeforces Round 150 [Rated for Div. 2-3 Moves 023 13n % 3 I don't want to deal with rounding. 2), Educational Codeforces Round 145 (Rated for Div. Hopefully for better luck next time :((, Problem C Can anyone tell me how the answer here is "yes", s = "01342104424232424004113131423112311240" ,,,,m = 5 , l = 23004 , r = 24244. 2), CodeforcesEducational Codeforces Round 121 (Rated for Div. Can't think of any approach for C? You can read the details about the cooperation between Harbour.Space University and Codeforces in the blog post.. If $$$d_1$$$ does not appear at all in the string $$$s$$$, then we output "YES" because $$$d_1$$$ will definitely work. On Jun/12/2023 17:35 (Moscow time) Educational Codeforces Round 150 (Rated for Div. Then it's optimal to choose K as one of the elements of C. (Sketch of proof: if we choose K between two values of C, we can raise it up to the next value of C without making anything worse.). mod : 0' will be auto-vectorized in GCC with AVX enabled so that's a reason I guess. 2) 4: 332: Special Offer! 2), Educational Codeforces Round 39 (Rated for Div. 1), CodeforcesCodeforces Round #784 (Div. Edit: Got it now. 2) will start. I still do not understand what a_i is tho, could you please clear that? Such violation of the rules may be the reason for blocking your account or other penalties. Does anyone have a testcase that breaks my submission for C? So, Now, Traverse the string S from left to right. Let's pray that god will be generous and allow us to advance to the next color. If nothing happens, download GitHub Desktop and try again. Rating will be k after that. I didn't imagine so many people would stumble at A. 2), Educational Codeforces Round 52 (Rated for Div. Better intuitive approach to the problem C, My approach for problem C, Binary search the waiting time before starting to move. 2) will start. 3), CodeforcesEducational Codeforces Round 128 (Rated for Div. 2), Educational Codeforces Round 46 (Rated for Div. This round will be rated for the participants with rating lower than 2100. 2), Educational Codeforces Round 59 (Rated for Div. 2), CodeforcesCodeforces Round #785 (Div. In the simple case when all of $$$one_{i-\sqrt k}, \dots, one_i$$$ stand one after the other you will need to make at least $$$(\sqrt k + 1)^2$$$ operations, and if they are not consecutive it requires even more operations. where right[k][j] gives the closest index of j to the right of kth position in s. right array can be precalculated. In case of repeated violations, your account may be blocked. Still it passed during contest. Why is this solution showing MLE in pypy3? $$$sum1 += K$$$ implies that the step length is $$$K$$$. !, you are too slow !! \\, =\sum_{i=0}^n \binom{n}{i} a^i b^{n-i} \sum_{j=0}^k \left\{\begin{matrix} k\\j \end{matrix} \right\}i^{\underline{j}} = \sum_{j=0}^k \left\{\begin{matrix} k\\j \end{matrix} \right\}\sum_{i=0}^n \binom{n}{i} a^i b^{n-i} i^{\underline{j}} ohhh.I know.it's not enough!max step should be calculated.can't be set sqrt(n), Would any kind-hearted person mind explaining to me why "the sum of F^k over all possible combinations is equal to the sum of G(t) over all possible tuples t"? dud u burn in hell like this what are u even saying? 2), Educational Codeforces Round 100 (Rated for Div. I am not able to figure out why they are equal, what is the intuition behind and how could we prove it (the rest is straightforward tho, just can't comprehend the rephrased problem). $$$dp_i,_j$$$ = $$$\sum_{w=1, q=k+j-1}^{i - wq >= 0} dp_{i - wq},_{j - 1}$$$. Here in this video we have discussed the approach to solve A. wait, shouldn't the top left element in each grid be 0? So rewriting the sum, we can compute the last part since the indices of the bags from which we pick odd balls are fixed, We arrive at finall formula we can compute in $$$O(k)$$$ (not taking in account the precomputations) after noticing that. If we pick K = C[i], then the total score obtained is C[N] + (C[i] min C[i..N]). I came out with a greedy approach in O(m). https://codeforces.com/contest/1845/submission/211531378. If $$$n \bmod 3 = 0$$$, then the answer is $$$\frac{n}{3}$$$. 2), Initial revision for English translation (saved to drafts). Your formula would include $$$dp_{0, 0} = 1$$$ ($$$w = 1$$$, $$$q = 3$$$) in the summation, but the actual value of $$$dp_{3, 1}$$$ is $$$0$$$. Here are some less complex observations for problem D : Let's make a prefix array first. 2), Educational Codeforces Round 148 (Rated for Div. could you please provide the link of the question which you are talking about? 2), Educational Codeforces Round 33 (Rated for Div. 2), Educational Codeforces Round 149 (Rated for Div. They should have kept more tests. To see all available qualifiers, see our documentation. const int MAXN=1e5+50; 1 + Div. 2), Educational Codeforces Round 58 (Rated for Div. Hello Codeforces! You will complete 15 modules (each three weeks long) in one year. #include Don't we?? Is that where the (maximum distance you go below from k in you prefix array) in your solution comes into play? I might become cyan by morning if not hacked. 2) Finished Practice? 2), Educational Codeforces Round 125 (Rated for Div. Note that unintentional leakage is also a violation. config.pyapi_keyhypixelsecrets.py imin f[k]+1( kn; On Jul/27/2023 17:35 (Moscow time) Educational Codeforces Round 152 (Rated for Div. Such violation of the rules may be the reason for blocking your account or other penalties. Any traders realized that D was just maximum drawdown in your average backtest haha? 2), Harbour.Space Scholarship Contest 2021-2022 (open for everyone, rated, Div. I am still not able to convince myself how the prefix sum just behind the minimum subarray is the answer. As someone has written, it might work not in $$$O(NK^2)$$$ but in $$$O(NK\sqrt{K}$$$). who tested this round?? The idea is if I can check whether I can walk through all the grid without getting stuck with a certain starting waiting time. n^3 Otherwise, the answer is $$$\frac{n - 4}{3} + 2$$$. If you use this then there is only $$$O(n\cdot k^{1.5})$$$ states. In case of repeated violations, your account may be blocked. Let $$$\mathbf{nxt}$$$ be a $$$10$$$ by $$$|s|+1$$$ array such that $$$\mathbf{nxt}[i][j]$$$ is the (1-based) position of the next occurrence of the digit $$$i$$$ after position $$$j$$$ in $$$s$$$, or INF if no such position exists. You will be given 6 or 7 problems and 2 hours to solve them. This round will be rated for the participants with rating lower than 2100. 2), Educational Codeforces Round 77 (Rated for Div. I don't know why am I getting wrong answer. I think pref_sum[i] should also be included? #include There was a problem preparing your codespace, please try again. How I visualized it is like this: consider first the $$$m=1$$$ case. 20 . Is D's time limit too strict? You can read the details about the cooperation between Harbour.Space University and Codeforces in the blog post. This will occur only at the minimum of the prefix sum array (let us call this index $$$mn$$$). please can someone help me rectify my code. There is a commented while block that may be easier to read, since it builds the entire 2D table instead of maintaining only 2 rows. Since we excluded the special case of $$$n = 1$$$, the value of $$$n$$$ must be at least $$$4$$$, and $$$n - 4$$$ must be divisible by $$$3$$$. 2), UNIQUE VISION Programming Contest 2023 Summer(AtCoder Beginner Contest 312) Announcement, How do I get blue in codeforces in 1 month, Codeforces Round 887 (Div 1, Div 2) Tutorial, 2022-2023 Southern And Volga Russian Regional - Editorial, Teams going to ICPC WF 2022 (Egypt 2023) WIP List. There was no rating changes for me after this contest even though i'm in div 2. For all such digits let's find their first positions in the string. Minimize diameter of tree by applying almost k.operations. ,,,DP.O(n\sqrt{n}). Educational Codeforces Round 133 (Rated for Div. So first we notice that parity of the sum of position of 1 changes if k is odd. See my submission for more details: 211498000, Nice approach, very easy to understand, tysm. Contest Id Start Time Contest Name Contest Phase Contest Frozen? Similarly, do this for all password positions, index always moves forward. True it is a little overkill but still its cool. ABCDdp dp D Codeforces / Educational Codeforces Round 133 (Rated for Div. Contest Duration (Seconds) Contest Relative Time; 1853: July 23, 2023, 2:35 p.m. Codeforces Round 887 (Div. Of course, for pos[d] I store indexes where digit d appears in s (in reverse order). I overkilled C with DP and I don't feel good now Submission. I understood your approach but could you please tell me what this line does? A goodThe second category Stelin numberTitle, of course, if you do n't know the knowledge, you know the function of the function, and you can also launch the formula (I belong to the latter). Consider the combinatorial meaning of the red part. \\, \binom{n}{i} i^{\underline{j}} = n\binom{n-1}{i-1} (i-1)^{\underline{j-1}}, \sum_{i=0}^n \binom{n}{i} a^i b^{n-i} i^{\underline{j}} = na\sum_{i=0}^{n-1} \binom{n-1}{i}a^ib^{n-1-i}i^{\underline{j-1}}, f[n][j] = m^{n-j}n^{\underline{j}}a^j, \sum_{j=0}^k \left\{\begin{matrix} k\\j \end{matrix} \right\} f[n][j], f[n][j] = f[n][j-1]/m*(n - j + 1)*a Please anybody give me hint in D problem. oh my god. I have a O(n^2 k) DP which TLEs. 2), Educational Codeforces Round 135 (Rated for Div. #include Cant wait to become rated. I'm a little confused by the expression, since it has a single summation controlled by two variables, so do you mean that we try every possible combination of $$$w$$$ and $$$q$$$ that satisfies $$$w \geq 1$$$, $$$q \geq k + j - 1$$$, and $$$i - wq \geq 0$$$? You will complete 15 modules (each three weeks long) in one year. I didn't do that, and had not big time. 2), Educational Codeforces Round 57 (Rated for Div. typedef long long ll; while (n--){ 2), Educational Codeforces Round 51 (Rated for Div. Now let's try the $$$m=2$$$ case. Minimize diameter of tree by applying almost k.operations. you are closer now. Codeforces: Experimental Educational Round: VolBIT Formulas Blitz: 2: 188: Alyona and flowers: Codeforces: Codeforces Round #381 (Div. #include If it has a solution better than $$$O(N*K^2)$$$ that I cannot be able to find then it is okay but if the original solution is to make optimizations on $$$O(N*K^2)$$$ then it is really bad! can anyone share their greedy/binary search approach for C? 2), Educational Codeforces Round 117 (Rated for Div. I proposed a DP solution. The course covers programming fundamentals and builds on prior knowledge, focusing on problem-solving, critical thinking, and project-based learning Intermediate: Become a pro-grammarians by diving into the main concepts of web and game development. I believe this is merely a coincidence, as the solution to problem D is fairly straightforward. 2), CodeforcesCodeforces Round #797 (Div. On Jul/08/2022 17:35 (Moscow time) Educational Codeforces Round 131 (Rated for Div. I solved this question and I still don't understand the intuition behind it. cuzz we won't let our rating fall from a point where we reached , so out k must be a value we reached. "educational codeforces round 115 (rated for div. 2), Educational Codeforces Round 150 (Rated for Div. Realizing how to make it run in $$$\mathcal{O}(NK^2)$$$. There are no optimizations other than the fact that if more than half the array is ones, you can swap them with 0s. Learning how to walk slowly to not miss important things. Algolia Hello Codeforces! 2), Educational Codeforces Round 124 (Rated for Div. Thanks! What's in blue when you can become cyan with no efforts. Codeforces Practice Tracker Browser Extension, Educational Codeforces Round 152 [Rated for Div. . It seems to be correct as that's I what I've done. But it gave RE on test 3 in system tests. I am curious to know. this example was a good hint for this approach but i didn't get it that time. More information can be found at http://codeforces.com/blog/entry/8790. Can somebody help with this submision, It takes O(m) time and I get time limit. We can calculate answer for each prefix value (though it's easy to prove that optimal value is always a local maximum). 2), Educational Codeforces Round 72 (Rated for Div. 2), Educational Codeforces Round 74 (Rated for Div. Write out the formula: $$$dp[i][k][p1] = dp[i - 1][abs(k - pos[p1 - 1])][p1 - 1]$$$, where $$$i$$$ is the current position, $$$k$$$ is the number of wasted moves, and $$$p1$$$ is the number of wasted moves so far. 2), Educational Codeforces Round 130 (Rated for Div. 2] By awoo , history , 5 weeks ago , translation, Hello Codeforces! Hjrtur is the CEO of 14islands, a design and development studio from Stockholm in Sweden and Floripa in Brazil. I've searched every nook and cranny in this entire universe and can now confidently say better than anybody that truly nobody tested [Music] the contest. With how unusually long the editorial for C is, I'm surprised that the problem-setters still felt it was appropriate to keep it as a Div2C. 2), Educational Codeforces Round 142 (Rated for Div. 2), Educational Codeforces Round 36 (Rated for Div. Let dp[i] denote the maximum index of elements l_i to r_i in s due to which a subsequence = pass[1i] is produced. For the first digit $$$d_1$$$ we do the exact same as above, but this time even if every possible $$$d_1$$$ between $$$l_1$$$ and $$$r_1$$$ appear, we might still be able to generate a valid passcode if $$$d_2$$$ doesn't appear in the string $$$s$$$ after $$$d_1$$$ does. $$$dp_0,_0 = 1$$$. Generally there will be a way to solve that problem with Binarysearch, Solution to 1716F - Bags with Balls using the multinomial theorem, Let $$$ B $$$ iterate through all the ways $$$ (b_1,\dots, b_n) $$$ to take the balls out of the bags and define $$$ g(x):= x\text{ mod } 2 $$$, and $$$F(B):=\text{# of odd balls}$$$. Lol:). (Sorry for bad English T_T). D. Chip Move- Educational Codeforces Round 133 dp D. Chip Move nk 1 - n0 k k+1 i1 <= k <= n <= 2e5 j ii - (k + j - 1) ji - (k + j - 1) i n \ (\sqrt (n)\) xdp [i] x - 1i - (x + j - 1) iniya[i][j] + j - y + 1,a[i][j] + j. EF !, 339 0 24 2 0 0, ero_engine, ACMervCodeforces Round #768 (Div. I think a simple counterexample is $$$dp_{3, 1}$$$ for $$$k = 2$$$ (the third entry in the sample output 2 of the problem). Note that unintentional leakage is also a violation. Can someone give a hint to solve D using Binary Search? #define pb push_back Take a look at Ticket 16020 from CF Stress for a counter example. Programming competitions and contests, programming community. My submission was having an indexing issue in all cases. Educational Codeforces Round 133 (Rated for Div. Just register for practice and you will be able to submit solutions. The expression 'sum[q] -= (sum[q] >= mod) ? You can consider the optimal scenario for each digit and try to solve this problem using a greedy approach. If we let $$$g_{i} = f_{i}(p) p^{i}$$$, then: where $$$S(i,j)$$$ is stirling number of the second kind. Just adjusting some int/long long representations and whether printing the newline operator can change TLE to AC. So I didn't copy it from any of the online sources. At any point, if the index becomes infinite (i.e. Naive implementation of this DP is $$$O(n^2k)$$$, but a state is useful only if $$$\left|j-S_i\right| <= O(\sqrt k)$$$ (where $$$S_i$$$ is the prefix sum of the original array), otherwise the number of swaps will be too large ($$$>k$$$). This is the first time I have received such a warning, and it is evidently a false positive. As a gray participant, I hope to stay gray after this contest), As a black and un-bolded participant, I hope to be black and un-bolded after this contest). 2), Educational Codeforces Round 86 (Rated for Div. Join us on a journey into the world of competitive programming. why in custom invocation my solution (of problem A) is working correctly, but when I submit, it says "Wrong answer on test 1" (that is example)? 2), CodeforcesCodeforces Round #788 (Div. I was thinking about something like doing a dp which keeps track of three parameters: current idx (n), current one, and wasted moves. :| I didn't read the explanation of test cases question was quite self explanatory! 2), Educational Codeforces Round 119 (Rated for Div. Start from last in both range strings(l and r) and string s, let say p1 = n-1, and p2 = m-1. Now, looking from last (i.e from p1 to 0), find the numbers in range l[p2] and r[p2], if at any p1, you find all the numbers in the range, then reduce p2, then again find all the numbers in range l[p2] and r[p2], do this until you will encounter one of the case, if p1 becomes -1, then that means you can make some password which will not be subsequence in string "s" therefore the Answer would be "YES", else p2 would have became -1, that means all the ranges have ended therefore all the possible subsequences are present in string "s", Hence the Answer would be "NO". Begin your programming adventure with us today. 2) will start. Want to solve the contest problems after the official contest ends? How to solve problem C if you can visit the cell more than once?? , 252 1 12 2 2 0, dianhsu, dianhsu: 836788039CodeforcesCodeforces Round #764 (Div. Hey everyone, Why the ratings I gained after this contest have decreased? Our goal is to create a password that contains any subsegment that does not exist in the given string as a subsequence in other words, We don't need to generate all possible subsequences of the given string, but We need to check for a combination that will not exist as subsequences this way we can use dp to optimize our brute force solution to find a sub-combination that will make a valid password. Which is why you should participate. What is the difference between calculated $$$dp_i,_j$$$ from the solution described above and calculated $$$dp_s,_i$$$ from the editorial? 2) . Such a coincidence is a clear rules violation. 2), Educational Codeforces Round 143 (Rated for Div. sign in No constraints on the rest of the balls. so we can greedily choose the number from possibilites (that is between l[i] and r[i]) which gives the shortest possible remaining string. If we choose k = prefix[i] and if there exists a j(>i), such that prefix[j] is the smallest among prefix[i+1n], then the elements from i+1 to j would contribute effectively nothing to the ratings. 2], I think I just did something crazy? 2), Educational Codeforces Round 40 (Rated for Div. :D, We can't do anything without the will of God. is it dp[i][j][p] = how many possible placements are there if the ith ball is at jth position and we have used p swaps so far, ( I just asked this to confirm if my idea was correct ). ], D: TL: 14; WA: 3. 2) A-D - cfHDUcf. There are only O(n) candidate ks and it is small enough to pass the problem D. i got either 0 or anyone of prefix sum value will be the answer.. but how to find which one will yield the maximum rating. [An uphack to D (WA) has been counted. 2), CodeforcesEducational Codeforces Round 136 (Rated for Div. 1 + Div. The elements of C are the scores that would be obtained if there wasn't a floor in effect. Educational Codeforces Round 133 Editorial By awoo , history , 12 months ago , translation, 1716A - 2-3 Moves Idea: vovuh Tutorial Solution (vovuh) 1716B - Permutation Chain Idea: BledDest Tutorial Solution (awoo) 1716C - Robot in a Hallway Idea: BledDest Tutorial Solution (awoo) 1716D - Chip Move Idea: BledDest Tutorial Solution (Neon) Any answer other than 2 will result in the player's rating decreasing from the -1. I solved it by trying all possible ks that can be the answer. 211508945, just find the largest decreasing subarray of input and avoid it, then we get the maximum rating. 2), Educational Codeforces Round 47 (Rated for Div. 2), Educational Codeforces Round 96 (Rated for Div. 2), Educational Codeforces Round 63 (Rated for Div. Requirements: Study Commitment: 3 hours/day. #include You signed in with another tab or window. 2) D 1849D Array Painting, n^2 like genuinely who tested? On Aug/04/2022 17:35 (Moscow time) Educational Codeforces Round 133 (Rated for Div. 2), Educational Codeforces Round 64 (Rated for Div. When I have chosen this new digit, I know its position in s (it is p), so for all digits from 0 to 9 I want to stop considering ones which happen to have positions <= p. Storing in reverse order is very beneficial because it lets me to delete element from a vector in O(1) and resulting complexity of solution is O(n + 10 * m). You could maybe see my solution for more clarification. Similarly, do this for all password positions, index always moves forward. After the end of the contest, you will have 12 hours to hack any solution you want.